Define Snell’s law of refraction. A ray of light is incident on a glass slab at an angle of incidence of 60°. If the angle of refraction be 32.7°, calculate the refractive index of glass.$(\text{Given:}\ \sin60^\circ=0.866,\text{ and }\sin32.7^\circ=540)$
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Snell's law: According to the Snell's law of refraction, the ratio of sine of angle of angle of refraction is constant for a given pair of media.$\text{Refractive index}=\frac{\text{Since of the angle of incidence}}{\text{Sine of the angle of refraction}}$
Given: Angle of incidence = 60° Angle of refraction = 32.4°$\text{Refractive index}=\frac{\text{Since of the angle of incidence}}{\text{Sine of the angle of refraction}}$
$\text{Refractive index}=\frac{\sin60^\circ}{\sin32.4^\circ}$
$\text{Refractive index}=\frac{0.866}{0.540}$
$\text{Refractive index}=1.603$
Given: Angle of incidence = 60° Angle of refraction = 32.4°$\text{Refractive index}=\frac{\text{Since of the angle of incidence}}{\text{Sine of the angle of refraction}}$
$\text{Refractive index}=\frac{\sin60^\circ}{\sin32.4^\circ}$
$\text{Refractive index}=\frac{0.866}{0.540}$
$\text{Refractive index}=1.603$
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