MCQ
Dimension of Capacitance is
- A$MLA ^{-1} T ^{4}$
- B$ML ^{2} A ^{-2} T ^{-4}$
- ✓$M ^{-1} L ^{-2} A ^{2} T ^{4}$
- D$M ^{-1} L ^{-1} A ^{2} T ^{2}$
$U=\frac{q^{2}}{2 C}$
$=\frac{(I t)^{2}}{2 C}$
Substitute the dimension of each term.
$M ^{1} L ^{2} T ^{2}=\frac{[ AT ]^{2}}{C}$
$C=\frac{[ AT ]^{2}}{ M ^{1} L ^{2} T ^{-2}}$
$= M ^{-1} L ^{-2} A ^{2} T ^{4}$
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Reason : The output voltage and the input voltage of the diode have $180^o$ phase difference.
| List $I$ | List $II$ |
| $A$ Isothermal Process | $I$ Work done by the gas decreases internal energy |
| $B$ Adiabatic Process | $II$ No change in internal energy |
| $C$ Isochoric Process | $III$ The heat absorbed goes partly to increase internal energy and partly to do work |
| $D$ Isobaric Process | $IV$ No work is done on or by the gas |
Choose the correct answer from the options given below :