Question
$\frac{{\cos {{10}^o} + \sin {{10}^o}}}{{\cos {{10}^o} - \sin {{10}^o}}} = $

Answer

a
(a) $\frac{{\cos {{10}^o} + \sin {{10}^o}}}{{\cos {{10}^o} - \sin {{10}^o}}}$

$ = \tan ({45^o} + {10^o}) = \tan {55^o}$.

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