Question
$\frac{d}{{dx}}\left( {\frac{{\log x}}{{\sin x}}} \right) = $

Answer

b
(b)$\frac{d}{{dx}}\left( {\frac{{\log x}}{{\sin x}}} \right) = \frac{{\frac{{\sin x}}{x} - \log x.\cos x}}{{{{\sin }^2}x}}$.

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