Question
$\frac{d}{{dx}}\sqrt {x\sin x} = $
$\therefore \frac{{dy}}{{dx}} = \frac{{[\sin x + x\cos x]}}{{2\sqrt {x\sin x} }}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
कथन $- 2: \int_{a}^{b} f(x) d x=\int_{a}^{b} f(a+b-x) d x .$