MCQ
$\frac{{dy}}{{dx}}\tan y = \sin (x + y) + \sin (x - y)$ નો ઉકેલ મેળવો.
- ✓$\sec y + 2\cos x = c$
- B$\sec y - 2\cos x = c$
- C$\cos y - 2\sin x = c$
- D$\tan y - 2\sec y = c$
$\frac{{dy}}{{dx}}(\tan y) = 2\sin x\cos y$ ==> $\frac{{\sin y}}{{{{\cos }^2}y}}dy = 2\sin xdx$
==> $\int {\frac{{\sin y}}{{{{\cos }^2}y}}} dy = 2\int {\sin xdx} $ ==> $\frac{1}{{\cos y}} = - 2\cos x + c$
$\therefore $ $\sec y + 2\cos x = c$.
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probabiliky that $X_1$ and $X_3$ are within earshot of each other is, Here, $\left.{ }^n C_r=\frac{n !}{(n-r) ! r !}\right)$
વિધાન ${\text{ - 2 : }}$ રેખા $\frac{{\text{x}}}{{\text{1}}}\,\, = \,\,\frac{{y\,\, - \,\,1}}{2}\,\, = \,\,\frac{{z\,\, - \,\,2}}{3}\,$ એ $A\,\,\left( {1,\,\,0,\,\,7} \right)$ અને $B\,\,\left( {1,\,\,6,\,3} \right)$ ને જોડતા રેખાખડને લંબ-દ્રીભાજે છે