Question
Draw a triangle ABC in which BC = 6cm, CA = 5cm and AB = 4cm. Construct a triangle similar to it and of scale factor $\frac{5}{3}.$
✓
Answer
Steps of construction:
1. Draw a line segment $B C=6 cm$.
2. Taking Sand Cas centres, draw two arcs of radii 4 cm and 5 cm intersecting each other at $A$.
3. Join $B A$ and $C A . \triangle A B C$ is the required triangle.
4. From $B$, draw any ray $B X$ downwards making at acute angle.
5. Mark five points $B_1, B_2, B_3, B_4$ and $B_5$ on $B X$, such that
$BB_1=B, B_2=B_2 B_3=B_3 B_4=B_4 B_5$
6. Join $B_3 C$ and from $B_5$ draw $B_5 M| | B_3 C$ intersecting the extended line segment $B C$ at
7. From point $M$ draw $M N \| C A$ intersecting the extended line segment $B A$ at $N$.
Then, $\triangle NBM$ is the required triangle whose sides is equal to $\frac{5}{3}$ of the corresponding sides of the $\triangle ABC$.
Hence, $\triangle NBM$ is the required triangle.
1. Draw a line segment $B C=6 cm$.
2. Taking Sand Cas centres, draw two arcs of radii 4 cm and 5 cm intersecting each other at $A$.
3. Join $B A$ and $C A . \triangle A B C$ is the required triangle.
4. From $B$, draw any ray $B X$ downwards making at acute angle.
5. Mark five points $B_1, B_2, B_3, B_4$ and $B_5$ on $B X$, such that
$BB_1=B, B_2=B_2 B_3=B_3 B_4=B_4 B_5$
6. Join $B_3 C$ and from $B_5$ draw $B_5 M| | B_3 C$ intersecting the extended line segment $B C$ at
7. From point $M$ draw $M N \| C A$ intersecting the extended line segment $B A$ at $N$.
Then, $\triangle NBM$ is the required triangle whose sides is equal to $\frac{5}{3}$ of the corresponding sides of the $\triangle ABC$.
Hence, $\triangle NBM$ is the required triangle.
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