During dehydration of alcohols to alkenes by heating with conc. $\ce{H_2SO_{4}},$ the initiation step is$:$
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Dehydration of alcohol to alkene in presence of concentrated $\ce{H_2SO_{4}}$ involves following steps$:$
Thus, the initiation step is protonation of alcohol.
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When $3-$methylbutan$-2-$ol is treated with $\ce{HBr},$ the following reaction takes place. What are the correct steps for formation of the above product?
What is the correct order of reactivity of alcohols in the following reaction?
$\text{R}-\text{OH}+\text{HCL}\xrightarrow{\text{ZnCl}_2}\text{R}-\text{Cl}+\text{H}_2\text{O}$