$\therefore \,\,C\, = \,\frac{1}{R}\, = \,\frac{1}{{31.6}}\,oh{m^{ - 1}}\,\, = \,0.0316\,oh{m^{ - 1}}$
Specific conductance
$=$ conductance $\times $ cell constant
$ = \,0.0316\,oh{m^{ - 1}}\,\, \times \,\,0.367\,c{m^{ - 1}}$
$ = \,0.0116\,\,oh{m^{ - 1}}c{m^{ - 1}}$
Now, molar concentration $=\,0.5\,M$ (given)
$=\,0.5\times 10^{-3}\,mole\,cm^{-3}$
$\therefore $ Molar conductance $=\,\frac {k}{molar \,conc.}$
$=\,\frac {0.0116}{0.5\times 10^{-3}}$
$=\,23.2\,S\,cm^2\,mol^{-1}$
$Zn^{2+}(aq) + 2e^{-} $ $\rightleftharpoons$ $ Zn (s)$ , $E^o_{RP}= -0.762\, V$,
$Cr^{3+}(aq) + 3e^{-} $ $\rightleftharpoons$$ Cr(s)$, $E^o_{RP} = -0.740\, V$
$2H^{+}(aq) + 2e^{-} $$\rightleftharpoons$$ H_2(g)$, $E^o_{RP} = 0.00\,V$,
$Fe^{3+}_{(aq)} + 2e^{-} $$\rightleftharpoons$$ Fe^{2+}(aq)$ , $E^o_{RP} = 0.77 \,V$
$Pt ( s )\left| H _{2}( g , 1 bar )\right| HCl ( aq \cdot, pH =1)| AgCl ( s )| Ag ( s )$
જલીય $HCL $ માટે $K \left( w _{0}=2.25 eV \right),$ ફોટોઇલેક્ટ્રિક પ્રવાહને રોકવા માટે જરૂરી $pH$ ................$\times 10^{-2}$ છે, બાકીની બધી અન્ય શરતો તે જ રહે છે
અહી આપેલ $2.303 \frac{ RT }{ F }=0.06 V ; E _{ AgC1|Ag|C ^{-}}^{0}=0.22\, V$