\( \Rightarrow \,\,\,\left( {440 \times \frac{1}{5}} \right) + \left( {120 \times \frac{4}{5}} \right)\)
\(\therefore \,\,\,\,{\text{P}}\) કુલ \({\text{ = 184}}\)
હવે, \({\text{P}}\) કુલ \( \times {{\text{Y}}_{\text{A}}}{\text{ = }}{{\text{P}}_{\text{A}}}\)
\(\therefore \,\,\,{\text{ }}{{\text{p}}_{\text{A}}}{\text{ = }}{{\text{p}}_{\text{A}}}^{\text{0}}{{\text{X}}_{\text{A}}}{\text{ = }}{{\text{Y}}_{\text{A}}}{\text{ }} \times {\text{ P}}\) કુલ
\(\,\therefore \,\,{Y_A} = \frac{{{p_A}^0{X_A}}}{P}\,\,\, = \,\,\,\frac{{440 \times \frac{1}{5}}}{{184}} = \frac{{88}}{{184}} = 0.478\)
(અણુભાર : $CHCl_3 = 119.5\, u, CH_2CI_2 = 85\,u$)
આણ્વિય દળ ${K}=39, {Mn}=55, {O}=16]$