d
\(P\) કુલ \({\text{ =  }}{{\text{p}}_{\text{A}}}^{\text{0}}{{\text{X}}_{\text{A}}}{\text{  +  }}{{\text{p}}_{\text{B}}}^{\text{0}}{{\text{X}}_{\text{B}}}\,\,\,\,\)

\( \Rightarrow \,\,\,\left( {440 \times \frac{1}{5}} \right) + \left( {120 \times \frac{4}{5}} \right)\)

\(\therefore \,\,\,\,{\text{P}}\) કુલ \({\text{ =  184}}\)

હવે, \({\text{P}}\) કુલ \( \times {{\text{Y}}_{\text{A}}}{\text{  =  }}{{\text{P}}_{\text{A}}}\)

\(\therefore \,\,\,{\text{ }}{{\text{p}}_{\text{A}}}{\text{  =  }}{{\text{p}}_{\text{A}}}^{\text{0}}{{\text{X}}_{\text{A}}}{\text{  =  }}{{\text{Y}}_{\text{A}}}{\text{ }} \times {\text{ P}}\) કુલ

\(\,\therefore \,\,{Y_A} = \frac{{{p_A}^0{X_A}}}{P}\,\,\, = \,\,\,\frac{{440 \times \frac{1}{5}}}{{184}} = \frac{{88}}{{184}} = 0.478\)