\(\left.\begin{array}{l}{\mathrm{B}_{1}=\frac{\mu_{0}}{4 \pi} \frac{\mathrm{I}_{1} \theta_{1}}{\mathrm{r}}} \\ {\mathrm{B}_{2}=\frac{\mu_{0}}{4 \pi} \frac{\mathrm{I}_{1} \theta_{1}}{\mathrm{r}}}\end{array}\right\} \Rightarrow \mathrm{B}_{1}=\mathrm{B}_{2}\)