So $m = 0.1$, Put the value of $m$ in $\Delta {T_b} = {K_b} \times m$
$\Delta {T_b} = 0.521 \times (0.1) = 0.0521$
$\mathrm{HX}(\mathrm{aq}) \rightleftharpoons \mathrm{H}^{+}(\mathrm{aq})+\mathrm{X}(\mathrm{aq}), \mathrm{Ka}=1.2 \times 10^{-5}$
$\left[\mathrm{K}_{\mathrm{n}}:\right.$ વિયોજન અચળાંક]
$300 \mathrm{~K}$ પર $HX$ ના $0.03 \mathrm{M}$ જલીય દ્રાવણ નું અભિસરણ (પરાસરણ) દબાણ .......... $\times 10^{-2}$ bar છે.
$\left[\right.$ આપેલ : $\mathrm{R}=0.083 \mathrm{~L} \mathrm{bar} \mathrm{Mol}^{-1} \mathrm{~K}^{-1}$ ]