\(\frac{V_o}{V_{\text {in }}}=\frac{R_0}{R_{\text {in }}} \times \beta=\frac{5 \times 10^3 \times 62}{500}=10 \times 62=620\)

\(V_o=620 \times V_{\text {in }}=620 \times 0.01=6.2 V\)

\(\therefore V_o=6.2\, volt.\)