Area of the image of the house formed on the screen \(=1.55 m ^{2}\)
\(=1.55 \times 10^{4} cm ^{2}\)
Arial magnification, \(m_{a}=\frac{\text { Area of image }}{\text { Area of object }}=\frac{1.55}{1.75} \times 10^{4}\)
\(\therefore\) Linear magnifications, \(m_{l}=\sqrt{m_{\alpha}}\) \(=\sqrt{\frac{1.55}{1.75} \times 10^{4}}=94.11\)