\(\frac{20}{6}= k (50-10)\)
\(\frac{40- T }{6}= K \left(\frac{40+ T }{2}-10\right)\)
From equation \((i)\) and \((ii)\)
\(\frac{20}{40- T }=\frac{40}{10+ T / 2}\)
\(10+\frac{ T }{2}=80-2\,T\)
\(\frac{5 T }{2}=70 \Rightarrow T =28^{\circ}\,C\)



જ્યાં $\sigma=$ સ્ટિફનનો અચળાંક છે.