Distance in first second ${h_{{\rm{first}}}} = 60 - \frac{g}{2}(2 \times 1 - 1) = 55\;m$
Distance in seventh second will be equal to the distance in first second of vertical downward motion ${h_{{\rm{seventh}}}} = \frac{g}{2}(2 \times 1 - 1) = 5\;m$
$⇒$ ${h_{{\rm{first}}}}/{h_{{\rm{seventh}}}}$$ = 11:1$