d
(d) Let the body after time \(t/2\) be at \(x\) from the top, then

\(x = \frac{1}{2}g\frac{{{t^2}}}{4} = \frac{{g{t^2}}}{8}\)…(i) .

\(h = \frac{1}{2}g{t^2}\)…(ii)

Eliminate \(t\) from (i) and (ii),

we get \(x = \frac{h}{4}\)

\(\therefore \) Height of the body from the ground \( = h - \frac{h}{4} = \frac{{3h}}{4}\)