Apparent depth \(=\frac{\mathrm{d}_{1}}{\mu_{1}}+\frac{\mathrm{d}_{2}}{\mu_{2}}+\dots\)
\(=\frac{5}{1.33}+\frac{1}{1.5}\)
\( \simeq 3.8+0.7 \simeq 4.5 \mathrm{cm}\)
\(\therefore \text { Shift }=6 \mathrm{cm}-4.5 \mathrm{cm} \cong 1.5 \mathrm{cm}\)
(શૂન્યવકાશમા પ્રકાશનો વેગ $=3 \times 10^{8} \,{m} / {s}$ અને $\left.\cos 30^{\circ}=\frac{\sqrt{3}}{2}\right)$