d
\(\begin{array}{l}
V = \sqrt {2gh} \, = \sqrt {2 \times 9.8 \times 50} = 14\sqrt 5 \\
S = \frac{{{v^2} - {u^2}}}{{2 \times 2}} = \frac{{{3^2} - 980}}{4} \approx 243\,m\\
Initially\,he\,has\,fallen\,50\,m.\\
\therefore \,Total\,height\,from\,where\\
he\,bailed\,out = 244 + 50 = 293\,m\,
\end{array}\)