(આપેલ : એન્ટીલોગ $antilog$ $0.125=1.333$,
$\text { antilog } 0.693=4.93 \text { ) }$
$83=\frac{200}{0.3} \log \frac{[ A ]_{0}}{[ A ]_{ t }}$
$0.125=\log \frac{[ A ]_{0}}{[ A ]_{ t }}$
$\frac{[ A ]_{0}}{[ A ]_{ t }}=1.333 \cong \frac{4}{3}$
$\therefore \frac{[ A ]_{ t }}{[ A ]_{0}} \times 100=\frac{3}{4} \times 100=75\, \%$
${I_2}\,\underset{{{K_{ - 1}}}}{\overset{{{K_1}}}{\longleftrightarrow}}\,2I\,$ (fast step)
$2I + {H_2}\xrightarrow{{{K_2}}}2HI$ (slow step)
તો પ્રક્રિયાનો વેગનિયમ જણાવો.