$Pt$ની સપાટી પર $NH _{3}$નું વિઘટન શૂન્ય ક્રમની પ્રક્રિયા છે. જો વેગ અચળાંકનું મૂલ્ય $2 \times 10^{-4}\,mole $ $liter^{-1}\, sec ^{-1}$ છે. $N _{2}$ અને $H _{2}$ના વેગ અનુક્રમે છે?

Question

A$N_2=$ $1 \times 10^{-4} \,mol ^{-1} \,sec ^{-1}$;

$H_2=$ $3 \times 10^{-4} \,mol ^{-1} \,sec ^{-1}$
B$N_2=$ $3 \times 10^{-4} \,mol ^{-1} \,sec ^{-1}$;

$H_2=$ $1 \times 10^{-4} \,mol ^{-1} \,sec ^{-1}$
C$N_2=$ $2 \times 10^{-4} \,mol ^{-1} \,sec ^{-1}$;

$H_2=$ $6 \times 10^{-4} \,mol ^{-1} \,sec ^{-1}$
D$N_2=$ $3 \times 10^{-4}\,mol ^{-1} \,sec ^{-1}$;

$H_2=$ $3 \times 10^{-4}\,mol ^{-1} \,sec ^{-1}$

AIIMS 2019, Medium

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Solution

c
The order of reaction is zero. The decomposition reaction of $NH _{3}$ is shown below :

$2 NH _{3} \rightarrow N _{2}+3 H _{2}$

Rate of formation of $N _{2}= k$

$=2 \times 10^{-4}\, mol \,L ^{-1} \,s ^{-1}$

Rate of formation of $H _{2}=3 k$

$=3 \times 2 \times 10^{-4} \,mol\, L ^{-1} \,s ^{-1}$

$=6 \times 10^{-4} \,mol \,L ^{-1}\, s ^{-1}$

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