Energy is being emitted from the surface of a black body at ${127^o}C$ temperature at the rate of $1.0 \times {10^6}J/\sec - {m^2}$. Temperature of the black body at which the rate of energy emission is $16.0 \times {10^6}J/\sec - {m^2}$ will be......... $^oC$
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(c)$\frac{{{E_2}}}{{{E_1}}} = {\left( {\frac{{{T_2}}}{{{T_1}}}} \right)^4}$
==>${T_2} = {\left( {\frac{{{E_2}}}{{{E_1}}}} \right)^{1/4}} \times {T_1} = {(16)^{1/4}} \times (273 + 127)$
==> T2 $ = 800\;K = {527^o}C$
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