$R = 8.314\, J\,K^{-1}\,mol^{-1} \,\,\,2.303 \times 8.314 \times 298 = 5705$
$\mathrm{Cd}_{(s)}+\mathrm{Hg}_{2} \mathrm{SO}_{4(s)}+\frac{9}{5} \mathrm{H}_{2} \mathrm{O}_{(l)} \rightleftharpoons \mathrm{CdSO}_{4} \cdot \frac{9}{5} \mathrm{H}_{2} \mathrm{O}_{(s)}+2 \mathrm{Hg}_{(l)}$
$25^{\circ} {C}$ પર ${E}_{\text {cell }}^{0}$નું મૂલ્ય $4.315\, {~V}$ છે.
જો $\Delta {H}^{\circ}=-825.2\, {~kJ} \,{~mol}^{-1}$, પ્રમાણિત એન્ટ્રોપી ફેરફાર $\Delta {S}^{\circ}$ ${J} \,{K}^{-1}$માં $........$ છે. (નજીકના પૂર્ણાંકમાં) [આપેલ: ફેરાડે અચળાંક $ = 96487 \, {C} \, {mol}^{-1} $]
${H_2}{O_{(l)}} \to \,\,H_{(aq)}^ + + \,\,OH_{(aq)}^ - \,;\,\,\,\Delta H\,\, = \,\,57.32\,\,KJ\,;$
${H_2}_{(g)} + \,\,\frac{1}{2}\,\,{O_2}_{(g)} \to \,\,{H_2}{O_{(1)}}\,;\,\,\Delta H\,\, = \,\, - 286.20\,\,KJ$