The reaction of acetic anhydride with ethanol yields ethyl acetate and ethanoic acid.
$\ce{(CH_3CO)_2O + CH_3CH_{2}OH \rightarrow CH_3COOCH_2CH_{3 }+ CH_3COOH}$
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Compound $\ce{C_2H_6O}$ has two isomers $X$ and $Y.$ On reaction with $HI, X$ gives alkyl iodide and water while $Y$ gives alkyl iodide and alcohol.Compounds $X$ and $Y$ are respectively: