d
For collision of a nenutron with deuterium \(:\)

Applying conservation of momentum\(:\)

\(m v+0=m v_{1}+2 m v_{2} \dots(i)\)

\(v_{2}-v_{1}=v \ldots(ii)\)

Therefore, Collision is elastic, \(e=1\)

From equ \((i)\) and equ \((ii)\) \(v_{1}=-v / 3\)

\(P_{d}=\frac{\frac{1}{2} m v^{2}-\frac{1}{2} m v_{1}^{2}}{\frac{1}{2} m v^{2}}=\frac{8}{9}=0.89\)

Now, for the collision of neutron with carbon nucleus

Applying conservation of momentum

\(m v+0=m v_{1}+12 m v_{2} \ldots\) \((iii)\)

\(v=v_{2}-v_{1}\)            \(...(iv)\)

\(v_{1}=-\frac{11}{13} v\)

\(P_{0}=\frac{\frac{1}{2} m v^{2}-\frac{1}{2} m\left(\frac{11}{13} v\right)^{2}}{\frac{1}{2} m v^{2}}=\frac{48}{169} \approx 0.28\)