Question
Explain with example α-decay.

Answer

i. The emission of α-particle from the nuclei of an radioelement is called α-decay.
ii. The charge on an α-particle is +2 with a mass of 4 u.
It is identical with helium nucleus and hence an α-particle is designated as

${ }_2^4 He$.
iii. In the $\alpha$-decay process, the parent nucleus ${ }_{ Z }^{ A X}$ emits an $\alpha$-particle and produces daughter nucleus $Y$. The parent nucleus thus loses two protons (charge +2 ) and two neutrons. The total mass lost is $4 u$. The daughter nucleus will therefore, have mass 4 units less and charge 2 units less than its parent.

iv. General equation for α-decay process can be given as:

Image

In α-decay process of radium, radon (daughter nuclei) is formed with loses of two protons (charge +2) and two neutrons. The total mass lost is 4 u.
Thus, radon has a mass of 4 units less and charge 2 units less than its parent radium.

Question H.
Energy produced in nuclear fusion is much larger than that produced in nuclear fission. Why is it difficult to use fusion to produce energy ?
Answer:

  • Nuclear fusion involves the fusion of lighter nuclei to form a heavy nucleus which is accompanied by an enormous amount of energy (heat).
  • Fusion reaction requires extremely high temperature typically of the order of 108 K.

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