Figure below shows a liquid being pushed out of the tube by a piston having area of cross section $2.0\,cm ^2$. The area of cross section at the outlet is $10\,mm ^2$. If the piston is pushed at a speed of $4\,cm s ^{-1}$, the speed of outgoing fluidis $.........\,cm s ^{-1}$.
JEE MAIN 2023, Easy
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By equation of continuity
$A _1 V _1= A _2 V _2$
$V _2=\frac{2 \times 4}{10 \times 10^{-2}}=80\,cm / s$
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