
$\frac{16 \mathrm{P}_{0}}{\mathrm{P}_{0}}=\left(\frac{2 \mathrm{V}_{0}}{\mathrm{V}_{0}}\right)^{\mathrm{x}}$
$x=4$
$\mathrm{w}=\frac{\mathrm{P}_{2} \mathrm{V}_{2}-\mathrm{P}_{1} \mathrm{V}_{1}}{1-\mathrm{x}}=\frac{2 \mathrm{P}_{0} \mathrm{V}_{0}-16 \mathrm{P}_{0} \mathrm{V}_{0}}{1-4}$
$=\frac{14}{3} \mathrm{P}_{0} \mathrm{V}_{0}$
