Question
Find the currents through the three reaiators shown in figure.
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Answer
- Current through (1) $4\Omega$ resistor = 0
- Current through (2) and (3)
(2) and (3) are in series,
$\text{R}_\text{eff}=4+6=10\Omega$
$\text{i}=\frac{2}{10}=0.2\text{A}$
Current through (2) and (3) are 0.2A.
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