The rate of radiation of a black body at $0°C$ is $E\,J/sec$ . The rate of radiation of this black body at ${273^o}C$ will be
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(a) $\frac{{{E_1}}}{{{E_2}}} = {\left( {\frac{{{T_1}}}{{{T_2}}}} \right)^4} \Rightarrow \frac{E}{{{E_2}}} = {\left( {\frac{{273 + 0}}{{273 + 273}}} \right)^4}$$ \Rightarrow {E_2} = 16\;E$.
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