Five resistors of given values are connected together as shown in the figure. The current in the arm $BD$ will be
AHalf the current in the arm $ABC$
B
Zero
CTwice the current in the arm $ABC$
DFour times the current in the arm $ABC$
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B
Zero
b (b) This is a balanced Wheatstone bridge circuit. So potential at $B$ and $D$ will be same and no current flows through $4R$ resistance.
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