Question
For an $AC$ circuit the potential difference and current are given by $V=10 \sqrt{2} \sin \omega t$ (in $V$ ) and $I=2 \sqrt{2} \cos \omega t$ (in $A$ ) respectively. The power dissipated in the instrument is ............ $W$
Here phase difference $\phi=\frac{\pi}{2}$
So, $P=V_{ rms } I_{ ms } \cos \frac{\pi}{2}=0$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.