A hemispherical bowl of radius $r$ is set rotating about its axis of symmetry in vertical. A small block kept in the bowl rotates with bowl without slipping on its surface. If the surface of the bowl is smooth and the angle made by the radius through the block with the vertical is $\theta$, then find the angular speed at which the ball is rotating.
  • A$\omega=\sqrt{ rg \sin \theta}$
  • B$\omega=\sqrt{ g / rcos \theta}$
  • C$\omega=\sqrt{\frac{ gr }{\cos \theta}}$
  • D$\omega=\sqrt{\frac{ gr }{\tan \theta}}$
AIIMS 2015, Diffcult
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