Fundamental frequency of an open pipe of length $0.5 m$ is equal to the frequency of the first overtone of a closed pipe of length $l$. The value of $l_c$ is $(m)$
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(b) First tone of open pipe = first overtone of closed pipe
$\Rightarrow$$\frac{v}{{2{l_0}}} = \frac{{3v}}{{4{l_c}}}$
$\Rightarrow$${l_c} = \frac{{3 \times 2 \times 0.5}}{4} = 0.75m$
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