Given below are two statements: one is labelled as Assertion $A$ and the other is labelled as Reason $R$
Assertion $A$: Steel is used in the construction of buildings and bridges.
Reason $R:$ Steel is more elastic and its elastic limit is high.
In the light of above statements, choose the most appropriate answer from the options given below
JEE MAIN 2023, Easy
Download our app for free and get started
Concept based
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1A $0.1 \mathrm{~kg}$ mass is suspended from a wire of negligible mass. The length of the wire is $1 \mathrm{~m}$ and its crosssectional area is $4.9 \times 10^{-7} \mathrm{~m}^2$. If the mass is pulled a little in the vertically downward direction and released, it performs simple harmonic motion of angular frequency $140 \ \mathrm{rad} \mathrm{s}^{-1}$. If the Young's modulus of the material of the wire is $\mathrm{n} \times 10^9 \mathrm{Nm}^{-2}$, the value of $\mathrm{n}$ isView Solution
- 2The adjacent graph shows the extension $(\Delta l)$ of a wire of length $1m$ suspended from the top of a roof at one end with a load $W$ connected to the other end. If the cross sectional area of the wire is ${10^{ - 6}}{m^2},$ calculate the young’s modulus of the material of the wireView Solution
- 3View SolutionThe elasticity of invar
- 4A body of mass $\mathrm{m}=10\; \mathrm{kg}$ is attached to one end of a wire of length $0.3\; \mathrm{m} .$ The maximum angular speed (in $rad \;s^{-1}$ ) with which it can be rotated about its other end in space station is (Breaking stress of wire $=4.8 \times 10^{7} \;\mathrm{Nm}^{-2}$ and area of cross-section of the wire $=10^{-2}\; \mathrm{cm}^{2}$ ) isView Solution
- 5In the given figure, two elastic rods $A$ & $B$ are rigidly joined to end supports. $A$ small mass $‘m’$ is moving with velocity $v$ between the rods. All collisions are assumed to be elastic & the surface is given to be frictionless. The time period of small mass $‘m’$ will be : [$A=$ area of cross section, $Y =$ Young’s modulus, $L=$ length of each rod ; here, an elastic rod may be treated as a spring of spring constant $\frac{{YA}}{L}$ ]View Solution
- 6For silver, Young's modulus is $7.25 \times {10^{10}}\,N/{m^2}$ and Bulk modulus is $11 \times {10^{10}}\,N/{m^2}$. Its Poisson's ratio will beView Solution
- 7If the ratio of diameters, lengths and Young's modulus of steel and copper wires shown in the figure are $p, q$ and $s$ respectively, then the corresponding ratio of increase in their lengths would beView Solution
- 8A wire is suspended by one end. At the other end a weight equivalent to $20\, N$ force is applied. If the increase in length is $1.0\, mm$, the increase in energy of the wire will be ....... $joule$View Solution
- 9One end of a uniform wire of length $L$ and of weight $W$ is attached rigidly to a point in the roof and a weight ${W_1}$ is suspended from its lower end. If $S$ is the area of cross-section of the wire, the stress in the wire at a height $3L/4$ from its lower end isView Solution
- 10A meter scale of mass $m$ , Young modulus $Y$ and cross section area $A$ is hanged vertically from ceiling at zero mark. Then separation between $30\ cm$ and $70\ cm$ mark will be :-( $\frac{{mg}}{{AY}}$ is dimensionless)View Solution