\(\Rightarrow V_T=\frac{2}{9} \times \frac{10 \times\left(10^{-4}\right)^2}{9.8 \times 10^{-6}}\left[10^5-10^3\right]\)
\(\Rightarrow V_T=224.5\)
when ball fall from height (\(h\))
\(\mathrm{V}=\sqrt{2 \mathrm{gh}}\)
\(\mathrm{h}=\left(\frac{\mathrm{V}^2}{2 \mathrm{~g}}\right)=2518 \mathrm{~m}\)