Download App

6.1. Equilibrium - 1 (chemical Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.1. Equilibrium - 1 (chemical Equilibrium)1 Mark
MCQ
${H_2} + {I_2}$ $\rightleftharpoons$ $2HI$ In the above equilibrium system if the concentration of the reactants at ${25\,^o}C$ is increased, the value of ${K_c}$ will
  • A
    Increase
  • B
    Decrease
  • ✓
    Remains the same
  • D
    Depends on the nature of the reactants
✓

Answer

Correct option: C.
Remains the same
c
in this reaction the value of $\Delta n$ is $o$

so after the increase temperature no change will happen so the $K_c$ is Remains the same

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 6.1. Equilibrium - 1 (chemical Equilibrium)→6.1. Equilibrium - 1 (chemical Equilibrium) — all question types→Chemistry STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

The $pH$ of $ 0.1 \,M$  solution of a weak monoprotic acid  $1\%$  ionized is
→
According to the reaction $PbC{l_2} = P{b^2} + 2C{l^ - },$the solubility coefficient of $PbC{l_2}$ is
→
Assign $A, B, C, D$ from given type of reaction.

$S{e_2}C{l_2}\xrightarrow{\Delta }SeC{l_4} + Se$

→
$Si_2O_7^{-6}$ anion is obtained when
→
Arrange $Ce^{3+}$, $La^{3+}$, $Pm^{3+}$, and $Yb^{+3}$ in increasing order of size
→
Super conductors are derived from compounds of:
→
What is the work function of the metal if the light of wavelength $4000\, \mathop A\limits^o $ generates photoelectrons of velocity $6\times10^5\, ms^{-1}$ from it? ............. $\mathrm{eV}$ (Mass of electron $= 9\times10^{-31}\, kg$ Velocity of light $= 3\times10^8\, ms^{-1}$ Planck’s constant $= 6.626\times10^{-34}\, Js$ Charge of electron $= 1.6\times10^{-19}\, J\,eV^{-1}$)
→
The total number of acylic isomers including the stereoisomers with the molecular formula ${C_4}{H_7}Cl$
→
Rate of reaction towards reduction using $(H_2 /Pt)$
→
The first line in the Balmer series in the $H$ atom will have the frequency :
→