MCQ
${H_2}\left( g \right) + \frac{1}{2}{O_2}\left( g \right) \to {H_2}O\left( g \right)$

$B.E. (H-H) = x_1 ; B.E. (O = O) = x_2$ ;

$B.E. (O -H) = x_3$

Heat of vaporisation of water $= x_4$ then $\Delta {H_f}$ [heat of formation of liquid water] is

  • A
    ${x_1} + \frac{{{x_2}}}{2} - {x_3} + {x_4}$
  • B
    $2{x_3} - {x_1}-\frac{{{x_2}}}{2} - {x_4}$
  • ${x_1} + \frac{{{x_2}}}{2} - 2{x_3} - {x_4}$
  • D
    ${x_1} + \frac{{{x_2}}}{2} - 2{x_3} + {x_4}$

Answer

Correct option: C.
${x_1} + \frac{{{x_2}}}{2} - 2{x_3} - {x_4}$
c
$\Delta H =( BE )_{\text {reactant }}-( BE )_{\text {proclucts }}$

But all the species must be in gaseous state.

In product, $\left[ H _2 O ( l ) \rightarrow H _2 O ( g )\right] \Delta H$ must be added.

Hence, $H _2( g )+\frac{1}{2} O _2( g ) \rightarrow H _2 O (l)$

$\Delta H =\left[( BE )_{ H - H }+\frac{1}{2}( BE )_{ O = O }\right]$

$=\left[(\Delta H )_{ vap }+2( BE )_{ O- H } \right]$

$=x_1+\frac{x_2}{2}-\left[x_4+2 x_3\right]$

$=x_1+\frac{x_2}{2}-x_4-2 x_3$

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