\(\frac{1}{\lambda}=\mathrm{K}\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)=\frac{\mathrm{K} \times 5}{36}\)

for \(\mathrm{N} \rightarrow \mathrm{L}\)

\(\quad \frac{1}{\lambda^{\prime}}=\mathrm{K}\left(\frac{1}{2^{2}}-\frac{1}{4^{2}}\right)=\frac{\mathrm{K} \times 3}{16}\)

\(\lambda^{\prime}=\frac{20}{27} \lambda\)