Therefore, weight of \(HCl\) in \(1\, ml\) of solution = specific gravity \(x \,49\, \%\)
\(=1.41 \times 49 / 100\)
\(=0.6909\, g / ml\)
Weight of \(HCl\) in \(1000\, ml\) of solution \(=0.6909 \times 1000=690.9\, g\)
Molarity = weight of \(HCl\) in \(1000\,ml /\) mol.weight of \(HCl\)
\(=690.9 / 36.4\)
\(=18.9 \,M\)
$(K_f =-1.86\,^o\, C/m)$