[આણ્વિય દળ: ${Ag}=108, {Br}=80$ ]
\(\Rightarrow {n}_{{Br}}={n}_{\lambda_{{kBt}}}=0.001\, {~mol}\)
\(\Rightarrow \text { mass }_{{Bz}}=(0.001 \times 80) \,{gm}=0.08 \,{gm}\)
\(\Rightarrow \text { mass } \%=\frac{0.08 \times 100}{0.2}=40 \,\%\)
$[$આણ્વિય દળ : સિલ્વર $=108$, બ્રોમિન $=80]$