$ = \,P_{Heptane}^o$ $x_{\text {heptane}}+P_{Oc\tan e}^o$ $x_{O c \tan e}$
$=105 \times \frac{25 / 100}{\frac{2}{100}+\frac{33}{114}}+45 \times \frac{35 / 114}{\frac{25}{100}+\frac{55}{114}}$
$=105 \times \frac{0.25}{0.25+0.3}+45 \times \frac{0.3}{0.25+0.3}$
$=\frac{105 \times 0.25}{0.55}+\frac{45 \times 0.3}{0.55}$
$=\frac{26.25+13.5}{0.55}=72\, k P a$
${K}_2 \mathrm{Cr}_2 \mathrm{O}_7$ & ${CuSO}_4$
SideX $SPM$ Side $\mathrm{Y}$ Due to osmosis :
(પાણી માટે $K_f = 1.86\,^oC\, kg\, mol^{-1}$ છે)
(મોલર દળ $S = 32\, g\, mol^{-1}, Na = 23\, g\, mol^{-1}$ )