Radius, \(r=\frac{d}{2}=0.25 \times 10^{-3} m\)
Compressional force, \(F=50000 N\)
Pressure at the tip of the anvil
\(p=\frac{\text { Force }}{\text { Arear }}=\frac{F}{\pi r^{2}}\)
\(=\frac{50000}{\pi\left(0.25 \times 10^{-3}\right)^{2}}\)
\(=2.55 \times 10^{11} Pa\)
Therefore, the pressure at the tip of the anvil is \(2.55 \times 10^{11} \;Pa\)
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