d
\(T.E = - K.E = \frac{{PE}}{2}\) The energy of electrons increases as they are away from the nucleus. The probability of finding the \(1s\) electron may be higher at \(a_0\) but the energy is not. The probability density of finding the electron is not zero at any place in the atom. So, the energy may be higher when it is far from \(a_0\)