Question
$i$. How do you classify elements into metals and non $-$ metals on the basis of their electronic configuration ? Choose metal and non $-$ metal out of the following : ${ }_{11}^{23} A,{ }_9^{19} B,{ }_{12}^{24} C,{ }_{15}^{31} D,{ }_{17}^{35} E$
$ii$. What type of bond will be formed if
$a.\ 'A\ '$ combines with $'B\ '$ ?
$b.\ 'A\ ' $ combines with $'E\ '$ ?
$c.\ 'C\ ' $ combines with $'E\ '$ ?
$d.\ 'D\ '$  combines with $'E\ '$ ?

Answer

$i$. Elements which contain $1$ to $3$ electrons in their outermost shell are metals.
Elements containing $4$ to $7$ electrons in their valence shell are non $-$ metals.
Electronic configurations:
${ }_{11}^{23} N a(Z=11)=2,8,1$
${ }_9^{19} B(Z=9)=2,7$
${ }_2^{24} C(Z=12)=2,8,2$
${ }_{31}^{21} D(Z=15)=2,8,5$
${ }_{35}^{15} E(Z=17)=2,8,7$
Hence $A$ and $C$ are metals whereas, $B, D$ and $E$ are non $-$ metals.
$ii.$ Type of bonds
$a.\ 'A\ '$ is metal and $'B\ '$ is non $-$ metal, so the bond formed will be ionic.
$A=2, 8,1 B = 2, 7$
Image
$b.\ 'A\ '$ is metal and $'E\ '$ is non $-$ metal, so the bond formed is ionic.
$A=2, 8, 1 B=2, 7$​​​​​​​
Image
$c.\ 'C\ ' $ is metal and $'E\ '$ is non $-$ metal, so the bond formed is ionic.
$C=2, 8, 2 E= 2, 8, 7$​​​​​​​
Image
$d.\ 'D\ '$ is a non $-$ metal and $'E\ '$ is also a non $-$ metal, so the bond formed will be covalent.
$D= 2,8,5    E= 2,8,7$
Image

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