Question

Identify which logic gate OR, AND and NOT is represented by the circuits in the dotted line boxes 1, 2 and 3. Give the truth table for the entire circuit for all possible values of A and B.

Answer

The dotted line box 1 represents NOT gate. The dotted line box 2 represents OR gate. The dotted line box 3 represents AND gate. The output of box 1 is $\bar{\text{A}}$ The inputs of box 2 are A and ?̅ As box 2 is OR gate, therefore, output of box 2 is $\text{E}=(\bar{\text{A}}+\text{B}).$ The inputs of box 3 are E and B Box 3 represents AND gate; therefore, output of box 3 is, $\text{Y}=\text{EB}=(\bar{\text{A}}+\text{B})\text{B}$ Truth table of the entire circuit is,
A
B
$\text{Y}=(\bar{\text{A}}+\text{B})\text{B}$
0
0
(1 + 0) . 0 = 0
1
0
(0 + 0) . 0 = 0
0
1
(1 + 1) . 1 = 1 . 1 = 1
1
1
(0 + 1) . 1 = 1 . 1 = 1

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