If a particle of charge ${10^{ - 12}}\,coulomb$ moving along the $\hat x - $ direction with a velocity ${10^5}\,m/s$ experiences a force of ${10^{ - 10}}\,newton$ in $\hat y - $ direction due to magnetic field, then the minimum magnetic field is
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(d) $F = qvB\sin \theta $ $==>$ $B = \frac{F}{{qv\sin \theta }}$
${B_{\min }} = \frac{F}{{qv}}$(when $\theta$ = $90^o$)
$\therefore \;{B_{\min }} = \frac{F}{{qv}} = \frac{{{{10}^{ - 10}}}}{{{{10}^{ - 12}} \times {{10}^5}}} = {10^{ - 3}}$ $Tesla$ in $U = \frac{{{B^2}}}{{2{\mu _0}}},$ $\hat z - $ direction.
${B_{\min }} = \frac{F}{{qv}}$(when $\theta$ = $90^o$)
$\therefore \;{B_{\min }} = \frac{F}{{qv}} = \frac{{{{10}^{ - 10}}}}{{{{10}^{ - 12}} \times {{10}^5}}} = {10^{ - 3}}$ $Tesla$ in $U = \frac{{{B^2}}}{{2{\mu _0}}},$ $\hat z - $ direction.
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