If a wire of length $1\, meter$ placed in uniform magnetic field $1.5\, Tesla$ at angle ${30^o}$ with magnetic field. The current in a wire $10\, amp$. Then force on a wire will be.......$N$
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(a) $F = Bil\sin {30^ \circ } = 1.5 \times 10 \times \frac{1}{2} = 7.5\,N$
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