If heat given to a system is $6 \,kcal$ and work done is $ 6 kJ.$ Then change in internal energy is ....... $kJ$
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(a)$\Delta Q = \Delta U + \Delta W$==> $\Delta U = \Delta Q - \Delta W$
$ = 6 \times 4.18 - 6 = 19.08kJ$$ \approx 19.1\,kJ$
$ = 6 \times 4.18 - 6 = 19.08kJ$$ \approx 19.1\,kJ$
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