If the breaking force for a given wire is $F$, If the thickness of the wire is doubled, then the breaking force will be
A$6F$
B$4F$
C$8F$
D$F$
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B$4F$
b (b) Breaking force $\propto$ $\pi {r^2}$
If thickness (radius) of wire is doubled then breaking force will become four times.
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